Question

A container with a volume of `48` `L` contains a gas with a temperature of `140` `K`. If the temperature of the gas changes to `90` `K` without any change in pressure, what must the container's new volume be?

Answer 1

Using the Combined Gas Law, `(P_1V_1)/T_1=(P_2V_2)/T_2`, but leaving out pressure because it remains constant, `V_1/T_1=V_2/T_2 to V_2=(V_1T_2)/T_1=(48*90)/140=30.9` `L`.