Question

A container with a volume of `48 L` contains a gas with a temperature of `140^o K`. If the temperature of the gas changes to `190 ^o K` without any change in pressure, what must the container's new volume be?

Answer 1

`65.143\ L`

Explanation:

Assuming the gas to be ideal then using ideal gas equation then by Charles law

At constant pressure, for a closed system

`V\propT`

`\frac{V_1}{V_2}=\frac{T_1}{T_2}`

`V_2=V_1(T_2/T_1)`

Given that the initial volume of gas is `V_1=48\ L` at initial temperature `T_1=140 \ K`. Now the final new volume `V_2` at temperature `T_2=190\ K` keeping pressure constant

`V_2=48(190/140)`

`=456/7`

`=65.143\ L`