A container with a volume of #48 L# contains a gas with a temperature of #210^o K#. If the temperature of the gas changes to #810 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-08-26T12:30:11

185 Liters (at 810 K)

Let me write down a scientific fact first. When we use Kelvin temperature scale, we do not use degrees sign. This is a scientific rule.

Now the question is

#P*V=n*R*T#

1st situation #48*V=n*R*210#

n and R are constants therefore #V=210/48#

2nd situation #210/48=810/?#

new volume will be #?=185 liters#