A container with a volume of #6 L# contains a gas with a temperature of #420^o K#. If the temperature of the gas changes to #370 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2018-04-19T06:39:38

The new volume is #=5.29L#

Apply Charles' Law

#" Volume "/" Temperature " = "Constant"#

#"At constant pressure"#

#V_1/T_1=V_2/T_2#

The initial volume is #V_1=6L#

The initial temperature is #T_1=420K#

The final tempertaure is #T_2=370K#

The final volume is

#V_2=T_2/T_1*V_1=370/420*6=5.29L#