A container with a volume of #7 L# contains a gas with a temperature of #360^o C#. If the temperature of the gas changes to #540 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-06-17T09:01:14

#V_f=5.97L#

#"initial volume of gas :"v_i=7L#

#"initial temperature of gas :"T_i=360 ^o=360+273=633 ^o K#

#"final temperature of gas :"540 ^o K#

#V_i/T_i=V_f/T_f#

#7/633=V_f/540#

#V_f=(540*7)/633#

#V_f=5.97L#