A container with a volume of #8 L# contains a gas with a temperature of #370^o C#. If the temperature of the gas changes to #510 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-11-24T08:30:48

The new volume is #=6.35L#

Apply Charles' Law

#V_1/T_1=V_2/T_2# at constant pressure

The initial volume is #V_1=8L#

The initial temperature is #T_1=370^@C+273=643K#

The final temperature is #T_2=510K#

The final volume is

#V_2=T_2/T_1*V_1=510/643*8=6.35L#