A cylinder has inner and outer radii of $12 cm$ and $18 cm$ , respectively, and a mass of $6 kg$ . If the cylinder's frequency of rotation about its center changes from $7 Hz$ to $3 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-07-26T06:59:19

The change in the angular momentum is $=3.53kgm^2s^-1$

The angular momentum is $L=Iomega$

For the cylinder, $I=m((r_1^2+r_2^2))/2$

So, $I=6*((0.12^2+0.18^2))/2=0.1404kgm^2$

The change in angular velocity is

$Delta omega=(7-3)*2pi=8pirads^-1$

The change in angular momentum is

$DeltaL=IDelta omega$

$=0.1404*8pi=3.53kgm^2s^-1$

A cylinder has inner and outer radii of 12 cm12 cm and 18 cm18 cm, respectively, and a mass of 6 kg6 kg. If the cylinder's frequency of rotation about its center changes from 7 Hz7 Hz to 3 Hz3 Hz, by how much does its angular momentum change?