A cylinder has inner and outer radii of 13 cm13cm and 15 cm15cm, respectively, and a mass of 6 kg6kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 2 Hz2Hz to 3 Hz3Hz, by how much does its angular momentum change?

1 Answer
Jan 30, 2017

The answer is =0.74kgms^(-1)=0.74kgms1

Explanation:

The angular momentum is L=IomegaL=Iω

where II is the moment of inertia

The change in angular momentum is

DeltaL=I Delta omega

For a cylinder, I=(m(r_1^2+r_2^2))/2

So, I=6*(0.13^2+0.15^2)/2=0.1182kgm^2

Delta omega=(3-2)*2pi

DeltaL=0.1182*2pi=0.74kgms^(-1)