A cylinder has inner and outer radii of $16 cm$ and $21 cm$ , respectively, and a mass of $3 kg$ . If the cylinder's frequency of rotation about its center changes from $4 Hz$ to $9 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-04-07T06:15:35

The change in angular momentum is $=3.28kgm^2s^-1$

The angular momentum is $L=Iomega$

Mass, $m=3kg$

For a cylinder, $I=m((r_1^2+r_2^2))/2$

So, $I=3*((0.16^2+0.21^2))/2=0.105kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

The change in angular velocity is

$Delta omega=(9-4)*2pi=(10pi)rads^-1$

The change in angular momentum is

$DeltaL=0.105*10pi=3.28kgm^2s^-1$

A cylinder has inner and outer radii of 16 cm16 cm and 21 cm21 cm, respectively, and a mass of 3 kg3 kg. If the cylinder's frequency of rotation about its center changes from 4 Hz4 Hz to 9 Hz9 Hz, by how much does its angular momentum change?