A cylinder has inner and outer radii of $16 cm$ and $24 cm$ , respectively, and a mass of $3 kg$ . If the cylinder's frequency of rotation about its center changes from $5 Hz$ to $2 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-02-24T14:28:23

The change in angular momentum is $=2.35kgm^2s^-1$

The angular momentum is $L=Iomega$

For a cylinder, $I=m(r_1^2+r_2^2)/2$

So, $I=3*(0.16^2+0.24^2)/2=0.1248kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

$Delta omega=(5-2)*2pi=6pi$

$DeltaL=0.1248*6pi=2.35kgm^2s^-1$

A cylinder has inner and outer radii of 16 cm16 cm and 24 cm24 cm, respectively, and a mass of 3 kg3 kg. If the cylinder's frequency of rotation about its center changes from 5 Hz5 Hz to 2 Hz2 Hz, by how much does its angular momentum change?