A cylinder has inner and outer radii of $16 cm$ and $24 cm$ , respectively, and a mass of $3 kg$ . If the cylinder's frequency of rotation about its center changes from $2 Hz$ to $7 Hz$ , by how much does its angular momentum change?

Question

1544 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-20T18:01:36

The angular momentum changes by $=3.92kgm^2s^-1$

The angular momentum is $L=Iomega$

The mass, $m=3kg$

For a cylinder, $I=m((r_1^2+r_2^2))/2$

So, $I=3*((0.16^2+0.24^2))/2=0.1248kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

The change in angular velocity is

$Delta omega=(7-2)*2pi=(10pi)rads^-1$

The change in angular momentum is

$DeltaL=0.1248*10pi=3.92kgm^2s^-1$

A cylinder has inner and outer radii of 16 cm16 cm and 24 cm24 cm, respectively, and a mass of 3 kg3 kg. If the cylinder's frequency of rotation about its center changes from 2 Hz2 Hz to 7 Hz7 Hz, by how much does its angular momentum change?