A cylinder has inner and outer radii of $2 cm$ and $16 cm$ , respectively, and a mass of $1 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $10 Hz$ to $15 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-02-02T07:30:01

The answer is $=0.41kgms^(-1)$

The angular momentum is $L=Iomega$

The change in angular momentum is

$DeltaL=IDelta omega$

$Delta omega$ is the change in angular velocity

For a cylinder, $I=m(r_1^2+r_2^2)/2$

So, $I=1*((0.02)^2+0.16^2)/2=0.013kgm^2$

$Delta omega=(15-10)*2pi=10pirads^-1$

$DeltaL=0.013*10pi=0.41kgms^(-1)$

A cylinder has inner and outer radii of 2 cm2 cm and 16 cm16 cm, respectively, and a mass of 1 kg1 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 10 Hz10 Hz to 15 Hz15 Hz, by how much does its angular momentum change?