A cylinder has inner and outer radii of $2 cm$ and $4 cm$ , respectively, and a mass of $12 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $4 Hz$ to $1 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-01-23T09:18:09

The change in angular momentum is $=18.14 kgms^-1$

The angular momentum is $L=Iomega$

For a cylinder, $I=(m(r_1^2+r_2^2))/2$

So, $I=12*((0.02^2+0.04^2))/2=0.9624kgm^2$

$DeltaL=0.9624(4-1)*2pi=0.9624*6pi=18.14kgms^(-1)$

A cylinder has inner and outer radii of 2 cm2 cm and 4 cm4 cm, respectively, and a mass of 12 kg12 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 4 Hz4 Hz to 1 Hz1 Hz, by how much does its angular momentum change?