A cylinder has inner and outer radii of $2 cm$ and $5 cm$ , respectively, and a mass of $8 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $12 Hz$ to $8 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-04-30T06:07:29

The change in angular momentum is $=0.29kgm^2s^-1$

The angular momentum is $L=Iomega$

Mass, $m=8kg$

For a cylinder, $I=m((r_1^2+r_2^2))/2$

So, $I=8*((0.02^2+0.05^2))/2=0.0116kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

The change in angular velocity is

$Delta omega=(12-8)*2pi=(8pi)rads^-1$

The change in angular momentum is

$DeltaL=0.0116*8pi=0.29kgm^2s^-1$

A cylinder has inner and outer radii of 2 cm2 cm and 5 cm5 cm, respectively, and a mass of 8 kg8 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 12 Hz12 Hz to 8 Hz8 Hz, by how much does its angular momentum change?