A cylinder has inner and outer radii of $3 cm$ and $9 cm$ , respectively, and a mass of $4 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $7 Hz$ to $6 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-06-16T05:47:09

The angular momentum changes by $=0.11kgm^2s^-1$

The angular momentum is $L=Iomega$

Mass, $m=4kg$

For a cylinder, $I=m((r_1^2+r_2^2))/2$

So, $I=4*((0.03^2+0.09^2))/2=0.018kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

The change in angular velocity is

$Delta omega=(7-6)*2pi=(2pi)rads^-1$

The change in angular momentum is

$DeltaL=0.018*2pi=0.11kgm^2s^-1$

A cylinder has inner and outer radii of 3 cm3 cm and 9 cm9 cm, respectively, and a mass of 4 kg4 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 7 Hz7 Hz to 6 Hz6 Hz, by how much does its angular momentum change?