A cylinder has inner and outer radii of $3 cm$ and $9 cm$ , respectively, and a mass of $4 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $9 Hz$ to $6 Hz$ , by how much does its angular momentum change?

Question

1463 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-22T06:17:52

The change in angular momentum is $=0.34kgm^2s^-1$

The angular momentum is $L=Iomega$

and $omega$ is the angular velocity

The mass of the cylinder is $m=4kg$

The radii of the cylinder are $r_1=0.03m$ and $r_2=0.09m$

For the cylinder, the moment of inertia is $I=m((r_1^2+r_2^2))/2$

So, $I=4*((0.03^2+0.09^2))/2=0.018kgm^2$

The change in angular velocity is

$Delta omega=Deltaf*2pi=(9-6) xx2pi=6pirads^-1$

The change in angular momentum is

$DeltaL=IDelta omega=0.018xx6pi=0.34kgm^2s^-1$

A cylinder has inner and outer radii of 3 cm3 cm and 9 cm9 cm, respectively, and a mass of 4 kg4 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 9 Hz9 Hz to 6 Hz6 Hz, by how much does its angular momentum change?