A cylinder has inner and outer radii of $4 c m$ $4 cm$ and $8 c m$ $8 cm$ , respectively, and a mass of $3 k g$ $3 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $5 H z$ $5 Hz$ to $8 H z$ $8 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-01-26T07:43:19

The change is $= 0.226 k g m s^{- 1}$ $=0.226kgms^(-1)$

The angular momentum is $L = I ω$ $L=Iomega$

and $DeltaL=IDeltaomega$

For a cylinder, $I=m/2(r_1^2+r_2^2)$

So, $I=3/2*(0.04^2+0.08^2)=3/2*0.008=0.012kgm^2$

$DeltaL=0.012*(8-5)*2pi=0.012*3*2pi=0.226kgms^(-1)$

A cylinder has inner and outer radii of 4 cm4cm4 cm and 8 cm8cm8 cm, respectively, and a mass of 3 kg3kg3 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 5 Hz5Hz5 Hz to 8 Hz8Hz8 Hz, by how much does its angular momentum change?