A cylinder has inner and outer radii of $5 cm$ and $6 cm$ , respectively, and a mass of $8 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $12 Hz$ to $15 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-07-19T06:05:47

The change in angular momentum is $=0.17kgm^2s^-1$

The angular momentum is $L=Iomega$

For a cylinder, $I=m(r_1^2+r_2^2)/2$

So, $I=3*(0.05^2+0.06^2)/2=0.00915kgm^2$

The change in angular velocity is

$Delta omega=(15-12)*2pi=6pirads^-1$

The change in angular momentum is

$DeltaL=IDelta omega$

$=0.00915*6pi=0.17kgm^2s^-1$

A cylinder has inner and outer radii of 5 cm5 cm and 6 cm6 cm, respectively, and a mass of 8 kg8 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 12 Hz12 Hz to 15 Hz15 Hz, by how much does its angular momentum change?