A cylinder has inner and outer radii of $5 cm$ and $6 cm$ , respectively, and a mass of $8 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $12 Hz$ to $17 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2018-01-15T18:00:39

The change in angular momentum is $=0.767kgm^2s^-1$

The angular momentum is $L=Iomega$

and $omega$ is the angular velocity

The mass of the cylinder is $m=8kg$

The radii of the cylinder are $r_1=0.05m$ and $r_2=0.06m$

For the cylinder, the moment of inertia is $I=m((r_1^2+r_2^2))/2$

So, $I=8*((0.05^2+0.06^2))/2=0.0244kgm^2$

The change in angular velocity is

$Delta omega=Deltaf*2pi=(17-12) xx2pi=10pirads^-1$

The change in angular momentum is

$DeltaL=IDelta omega=0.0244xx10pi=0.767kgm^2s^-1$

A cylinder has inner and outer radii of 5 cm5 cm and 6 cm6 cm, respectively, and a mass of 8 kg8 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 12 Hz12 Hz to 17 Hz17 Hz, by how much does its angular momentum change?