A cylinder has inner and outer radii of $5 cm$ and $9 cm$ , respectively, and a mass of $5 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $15 Hz$ to $8 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-05-16T08:48:28

The change in angular momentum is $=1.17kgm^2s^-1$

The angular momentum is $L=Iomega$

Mass, $m=5kg$

For a cylinder, $I=m((r_1^2+r_2^2))/2$

So, $I=5*((0.05^2+0.09^2))/2=0.0265kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

The change in angular velocity is

$Delta omega=(15-8)*2pi=(14pi)rads^-1$

The change in angular momentum is

$DeltaL=0.0265*14pi=1.17kgm^2s^-1$

A cylinder has inner and outer radii of 5 cm5 cm and 9 cm9 cm, respectively, and a mass of 5 kg5 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 15 Hz15 Hz to 8 Hz8 Hz, by how much does its angular momentum change?