A cylinder has inner and outer radii of $8 cm$ and $12 cm$ , respectively, and a mass of $6 kg$ . If the cylinder's frequency of rotation about its center changes from $7 Hz$ to $3 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-05-02T20:48:08

The angular momentum changes by $=1.57kgm^2s^-1$

The angular momentum is $L=Iomega$

Mass, $m=6kg$

For a cylinder, $I=m((r_1^2+r_2^2))/2$

So, $I=6*((0.08^2+0.12^2))/2=0.0624kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

The change in angular velocity is

$Delta omega=(7-3)*2pi=(8pi)rads^-1$

The change in angular momentum is

$DeltaL=0.0624*8pi=1.57kgm^2s^-1$

A cylinder has inner and outer radii of 8 cm8 cm and 12 cm12 cm, respectively, and a mass of 6 kg6 kg. If the cylinder's frequency of rotation about its center changes from 7 Hz7 Hz to 3 Hz3 Hz, by how much does its angular momentum change?