A cylinder has inner and outer radii of $8 c m$ $8 cm$ and $12 c m$ $12 cm$ , respectively, and a mass of $8 k g$ $8 kg$ . If the cylinder's frequency of rotation about its center changes from $3 H z$ $3 Hz$ to $2 H z$ $2 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-01-26T14:46:04

The answer is $= 0.523 k g m s^{- 1}$ $=0.523kgms^(-1)$

The angular momentum is $L = I ω$ $L=Iomega$

and $DeltaL=IDeltaomega$

For a cylinder, $I=m/2(r_1^2+r_2^2)$

So, $I=8/2*(0.08^2+0.12^2)=4*0.0208=0.0832kgm^2$

$Delta omega=(3-2)*2pi=2pi rads^-1$

$DeltaL=0.0832*2pi=0.523kgms^(-1)$

A cylinder has inner and outer radii of 8 cm8cm8 cm and 12 cm12cm12 cm, respectively, and a mass of 8 kg8kg8 kg. If the cylinder's frequency of rotation about its center changes from 3 Hz3Hz3 Hz to 2 Hz2Hz2 Hz, by how much does its angular momentum change?