A cylinder has inner and outer radii of 8 cm8cm and 16 cm16cm, respectively, and a mass of 6 kg6kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 2 Hz2Hz to 7 Hz7Hz, by how much does its angular momentum change?

1 Answer
Dec 18, 2016

The nasty part of this problem is in coming up with the moment of inertia for a thick-walled cylinder rotating along an axis through its centre. This is

I= m/2(r_1^2 +r_2^2)I=m2(r21+r22)

where r_1r1 and r_2r2 are the inner and outer radii, respectively.

In this case, I= 6/2(.08^2 +.16^2)I=62(.082+.162) = 0.096 kgm^20.096kgm2

Now, the angular momentum is defined as the product of its moment of inertia multiplied by the angular momentum (in radians/s don't forget!).

L=I L=Iomegaω

Since 1 Hz is equivalent to 2piπ radians, the angular velocity changes from 4piπ to 14piπ, and so, the change in angular momentum is found as follows:

L_i = 0.096 xx 4"piLi=0.096×4π = 0.3840.384pi#

L_f = 0.096 xx 14"piLf=0.096×14π = 1.3441.344pi#

DeltaL = 0.960pi kgm^2/s

(Hope you don't mind that I held back on the units until the last line. I thought they would make things a bit messy!)