A cylinder has inner and outer radii of $8 cm$ and $16 cm$ , respectively, and a mass of $6 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $9 Hz$ to $1 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-08-03T07:11:07

The change in angular momentum is $=4.83kgm^2s^-1$

The angular momentum is $L=Iomega$

The mass of the cylinder is $m=6kg$

The radii of the cylinder are $r_1=0.08m$ and $r_2=0.16m$

For the cylinder, $I=m(r_1^2+r_2^2)/2$

So, $I=6*(0.08^2+0.16^2)/2=0.096kgm^2$

The change in angular velocity is

$Delta omega=Deltaf*2pi=(9-1)*2pi=16pirads^-1$

The change in angular momentum is

$DeltaL=I Delta omega=0.096*16pi=4.83kgm^2s^-1$

A cylinder has inner and outer radii of 8 cm8 cm and 16 cm16 cm, respectively, and a mass of 6 kg6 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 9 Hz9 Hz to 1 Hz1 Hz, by how much does its angular momentum change?