A cylinder has inner and outer radii of $9 cm$ and $11 cm$ , respectively, and a mass of $5 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $12 Hz$ to $6 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-03-22T16:07:15

The change in angular momentum is $=1.90kgm^2s^-1$

The angular momentum is $L=Iomega$

For a cylinder, $I=m((r_1^2+r_2^2))/2$

So, $I=5*((0.09^2+0.11^2))/2=0.0505kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

The change in angular velocity is

$Delta omega=(12-6)*2pi=(12pi)rads^-1$

The change in angular momentum is

$DeltaL=0.0505*12pi=1.90kgm^2s^-1$

A cylinder has inner and outer radii of 9 cm9 cm and 11 cm11 cm, respectively, and a mass of 5 kg5 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 12 Hz12 Hz to 6 Hz6 Hz, by how much does its angular momentum change?