A cylinder has inner and outer radii of $9 cm$ and $16 cm$ , respectively, and a mass of $4 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $12 Hz$ to $4 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-03-15T14:44:57

The change in angular momentum is $=3.39kgm^2s^-1$

The angular momentum is $L=Iomega$

For a cylinder, $I=m(r_1^2+r_2^2)/2$

So, $I=4*(0.09^2+0.16^2)/2=0.0674kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

The change in angular velocity is

$Delta omega=(12-4)*2pi=16pirads^-1$

The change in angular momentum is

$DeltaL=0.0674*16pi=3.39kgm^2s^-1$

A cylinder has inner and outer radii of 9 cm9 cm and 16 cm16 cm, respectively, and a mass of 4 kg4 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 12 Hz12 Hz to 4 Hz4 Hz, by how much does its angular momentum change?