A generator produce 100kwatt power at a potential difference of 10 KV the power transmitted through cable of total resistance 5 ohm how much power dissipated in the cables?

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Answer 1 · 2018-07-31T21:45:44

$500 watts$ $"500 watts"$

$voltage \times current = power$ $"voltage" xx "current" = "power"$ .

Here

So

$"current" = "100,000 W"/"10,000 V" = "10 A"$

Now

$"power loss" = I^2xx R" "$ $["current squared" xx "resistance"]$

So

$"power loss" = ("10 A")^2 xx 5 \ Omega = "500 W"$ .