A line segment has endpoints at (1 ,6 )(1,6) and (6 ,7 )(6,7). The line segment is dilated by a factor of 4 4 around (4 ,3 )(4,3). What are the new endpoints and length of the line segment?

1 Answer
May 3, 2018

(1,6) to (-8,15)(1,6)(8,15)

(6,7) to (12, 19) (6,7)(12,19)

l = 4 sqrt{26}l=426

Explanation:

I did the general case [here.](https://socratic.org/questions/a-line-segment-has-endpoints-at-2-4-and-5-3-the-line-segment-is-dilated-by-a-fac-1#604871)

(p,q)=(4,3), quad r=4, quad (a,b)=(1,6), quad (c,d)=(6,7)

(a,b) to ( (1-r)p + ra, (1-r)q+ rb)

(1,6) to (-3(4)+4(1), -3(3) + 4(6)) = (-8,15)

(c,d) to ((1-r)p + rc, (1-r)q+ rd)

(6,7) to ( -3(4) + 4(6), -3(3) + 4(7)) = (12, 19)

new length l = r \sqrt{ (a-c)^2 + (b-d)^2 }

l = 4 \sqrt{(6-1)^2 + (7-6)^2} = 4 sqrt{26}