A line segment has endpoints at (1 ,9 )(1,9) and (6 ,7 )(6,7). The line segment is dilated by a factor of 4 4 around (4 ,3 )(4,3). What are the new endpoints and length of the line segment?

1 Answer
Nov 2, 2016

"the new end points of line segment are:(-8,27),(12,19)"the new end points of line segment are:(-8,27),(12,19)
"the length of line segment is :"sqrt 464the length of line segment is :464

Explanation:

enter image source here
"the point of D(4,3) is dilatation point"the point of D(4,3) is dilatation point

"the point F is image of B"the point F is image of B

"distance between BC is :"7-3=4distance between BC is :73=4

"distance between FG is :"4*"factor"=4*4=16distance between FG is :4factor=44=16

"y coordinate of F is :" 3+16=19y coordinate of F is :3+16=19

"distance between DC is :"6-4=2distance between DC is :64=2

"distance between DG is :"2*"factor"=2*4=8 distance between DG is :2factor=24=8

"x coordinate of F is :"4+8=12x coordinate of F is :4+8=12

"coordinates of F are :"F(12,19)coordinates of F are :F(12,19)

"The point of E is image of A"The point of E is image of A

"distance between AH is:"9-3=6distance between AH is:93=6

"distance between EI is:"6*"factor"=6*4=24distance between EI is:6factor=64=24

"y coordinate of E is :"3+24=27y coordinate of E is :3+24=27

"distance between HD is :"4-1=3distance between HD is :41=3

"distance between ID is :"3*"factor"=3*4=12distance between ID is :3factor=34=12

"the x coordinate of E is :"4-12=-8the x coordinate of E is :412=8

"coordinates of E are :"E(-8,27)coordinates of E are :E(8,27)

"length of line segment AB :"length of line segment AB :

bar (AB)=sqrt((6-1)^2+(7-9)^2)¯¯¯¯¯¯AB=(61)2+(79)2

bar (AB)=sqrt(25+4)=sqrt(29)¯¯¯¯¯¯AB=25+4=29

"length of line segment EF:"length of line segment EF:

bar (EF)=sqrt((12+8)^2)+(19-27)^2¯¯¯¯¯¯EF=(12+8)2+(1927)2

bar (EF)=sqrt(400+64)=sqrt(464)¯¯¯¯¯¯EF=400+64=464