A line segment has endpoints at (2 ,4 )(2,4) and (5 ,3 )(5,3). The line segment is dilated by a factor of 3 3 around (3 ,8 )(3,8). What are the new endpoints and length of the line segment?

1 Answer
Dec 29, 2017

New end points: hat(P): (0,-4)ˆP:(0,4) and hat(Q):(12,5)ˆQ:(12,5)
New segment length: abs(hat(P)hat(Q))=15ˆPˆQ=15

Explanation:

Let PP be the original point (2,4)(2,4)
Let QQ be the original point (5,3)(5,3)
and
Let CC be the center of dilation, (3,8)(3,8)

Consider the vector vec(CP)CP
color(white)("XXX")vec(CP)=(2,4)-(3,8)=(-1,-4)XXXCP=(2,4)(3,8)=(1,4)
Dilation by a factor of 33 will scale this vector up by a factor of 33
So PP will move to the new location:
color(white)("XXX")hat(P)=C+3vec(CP)XXXˆP=C+3CP
color(white)("XXXX")=(3,8)+3(-1,4)XXXX=(3,8)+3(1,4)
color(white)("XXXX")=(3-3,8-12)XXXX=(33,812)
color(white)("XXXX")=(0,-4)XXXX=(0,4)

Similarly
color(white)("XXX")vec(CQ)=(5,3)-(2,4)=(3,-1)XXXCQ=(5,3)(2,4)=(3,1)
and new location for QQ at
color(white)("XXX")hat(Q)=(3,8)+3(3,-1)XXXˆQ=(3,8)+3(3,1)
color(white)("XXXX")=(12,5)XXXX=(12,5)

The length of the new line segment will be (using the Pythagorean Theorem)
color(white)("XXX")abs(hat(P)hat(Q))=sqrt((12-0)^2+(5-(-4))^2)XXXˆPˆQ=(120)2+(5(4))2
color(white)("XXX")=sqrt(12^2+9^2)XXX=122+92
color(white)("XXX")=sqrt(225)XXX=225
color(white)("XXX")=15XXX=15