A painting measures 12 inches by 16 inches and is surrounded by a frame of uniform width around the four edges. The perimeter of rectangle formed by the painting and its frame is 72 inches. What is the width of the frame?

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Answer 1 · 2018-04-22T01:19:51

2 inches.

Let #x# be the frame's width. The width of the framed picture is #12+2x# and the height #16+2x# so the perimeter is

#72 = 2(12+2x) + 2(16+2x) = 56 + 8x#

#16 = 8x#

#x = 2# inches

Check: # 2 ( 16 + 20) = 72 quad sqrt #