If the area of a square is 225 cm2, what is perimeter?

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Answer 1 · 2017-10-03T01:50:40

See a solution process below:

The formula for the area of a square is:

$A = s^{2}$ $A = s^2$

Where:

$A$ $A$ is the area of the square.

$s$ $s$ is the length of the side of a square.

Substituting and solving for $s$ $s$ gives:

$225 {cm}^{2} = s^{2}$ $225" cm"^2 = s^2$

We can take the square root of each side of the equation giving:

$\sqrt{225 {cm}^{2}} = \sqrt{s^{2}}$ $sqrt(225" cm"^2) = sqrt(s^2)$

$15 cm = s$ $15" cm" = s$

$s = 15 cm$ $s = 15" cm"$

The formula for the perimeter of a square is:

$p = 4 s$ $p = 4s$

Where:

$p$ $p$ is the perimeter of the square.

$s$ $s$ is the length of the side of a square.

Substituting for $s$ $s$ from the solution for the previous formula and calculating $p$ $p$ gives:

$p = 4 \times 15 cm$ $p = 4 xx 15" cm"$

$p = 60 cm$ $p = 60" cm"$