Question

A pair of dice is tossed. How do you find the probability of the sum of the numbers being `8?`

Answer 1

`P(8) = 5/36`

Explanation:

You can draw up a possibility space and count how many of the outcomes meet the requirements.

The following array shows the sum of two dice thrown.
(Created by Parzival)

`{: (color(white)(0)," "ul1" "," "ul2" "," "ul3" "," "ul4" "," "ul5" "," "ul6" "),(1|," "2" "," "3" "," "4" "," "5" "," "6" "," "7" "),(2|," "3" "," "4" "," "5" "," "6" "," "7" "," "color(blue)(8)" "),(3|," "4" "," "5" "," "6" "," "7" "," "color(blue)(8)" "," "9" "),(4|," "5" "," "6" "," "7" "," "color(blue)(8)" "," "9" "," "10" "),(5|," "6" "," "7" "," "color(blue)(8)" "," "9" "," "10" "," "11" "),(6|," "7" "," "color(blue)(8)" "," "9" "," "10" "," "11" "," "12" ") :}`

There are `6xx6 =36` outcomes and of these there are `5` ways that a total of `color(blue)(8)` can be obtained.

`:. P(8) = 5/36`