A projectile is shot from the ground at a velocity of $11 \frac{m}{s}$ $11 m/s$ at an angle of $\frac{π}{6}$ $pi/6$ . How long will it take for the projectile to land?

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A projectile is shot from the ground at a velocity of $11 \frac{m}{s}$ $11 m/s$ at an angle of $\frac{π}{6}$ $pi/6$ . How long will it take for the projectile to land?

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Answer 1 · 2016-02-05T18:39:08

$x_{m} = 6, 5 . 1, 942 = 12, 623 m$ $x_m=color(red)(6,5). color(green)(1,942)=12,623 m$

Explanation:

$v_{i x} = v_{i} . cos θ$ $v_(ix)=v_i. cos theta$
$v_(ix)=11. cos (cancel(pi)/6 *180/cancel(pi))$
$v_(ix)=11. cos 60$
$v_(ix)=11.0,5=6,5 m/s$
$color(red)(v_(ix)=6,5 m/s" initial velocity x component")$

$t_e=(2.v_i sin theta)/g$
$t_e=(2.11.sin 60)/g$
$t_e=(22. 0,866)/(9,81)$
$color(green)(t_e=1,942 s" elapsed time")$
$x_m=v_(ix). t_e$
$x_m=color(red)(6,5). color(green)(1,942)=12,623 m$

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A projectile is shot from the ground at a velocity of $11 \frac{m}{s}$ $11 m/s$ at an angle of $\frac{π}{6}$ $pi/6$ . How long will it take for the projectile to land?

1 Answer

Explanation:

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A projectile is shot from the ground at a velocity of $11 \frac{m}{s}$ $11 m/s$ at an angle of $\frac{π}{6}$ $pi/6$ . How long will it take for the projectile to land?