A projectile is shot from the ground at a velocity of $12 m/s$ and at an angle of $(pi)/2$ . How long will it take for the projectile to land?

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Answer 1 · 2016-11-02T14:52:55

Here, $u= 12m/s$ , $theta = pi/2$

$t = (2usintheta)/g$

$t= (2xx12xx1)/10$

$t= 2.4 sec$

It will take 2.4 seconds for the projectile to land.

A projectile is shot from the ground at a velocity of 12 m/s12 m/s and at an angle of (pi)/2(pi)/2. How long will it take for the projectile to land?