A projectile is shot from the ground at a velocity of $18 m/s$ and at an angle of $(2pi)/3$ . How long will it take for the projectile to land?

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Answer 1 · 2016-02-11T18:13:54

$t~=3,18 s$

$t=(2*v_i*sin alpha)/(g) " elapsed time"$
$alpha=(2pi)/3*180/pi=120^o$
$sin 120^o=sin 60^o~=0,866$
$t=(2*18*0,866)/(9,81)$
$t~=3,18 s$

A projectile is shot from the ground at a velocity of 18 m/s18 m/s and at an angle of (2pi)/3(2pi)/3. How long will it take for the projectile to land?