Question

A projectile is shot from the ground at a velocity of `18 m/s` at an angle of `pi/6`. How long will it take for the projectile to land?

Answer 1

`T=1.8367s`

Explanation:

Data:-
Velocity`=v_0=18m/s`
Angle`=theta=pi/6`
Time of flight`=T=??`
Acceleration due to gravity`=g=9.8m/s^2`
Sol:-
We know that:
`T=(2v_0sintheta)/g`
`implies T=(2*18Sin(pi/6))/9.8=(36*0.5)/9.8=18/9.8=1.8367s`
`implies T=1.8367s`