A projectile is shot from the ground at a velocity of $19 \frac{m}{s}$ $19 m/s$ and at an angle of $\frac{π}{2}$ $(pi)/2$ . How long will it take for the projectile to land?

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A projectile is shot from the ground at a velocity of $19 \frac{m}{s}$ $19 m/s$ and at an angle of $\frac{π}{2}$ $(pi)/2$ . How long will it take for the projectile to land?

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Answer 1 · 2015-12-28T12:03:07

The projectile takes $3.87 s$ $3.87s$ to land.

Explanation:

In this particular case there is only the vertical component of motion (because angle is 90°). We consider the equation $s = v t - \frac{1}{2} a t^{2}$ $s=vt-1/2at^2$ and assume $s = 0$ $s=0$ . So $t (v - \frac{1}{2} a t) = 0$ $t(v-1/2at)=0$ and $t = 2 \frac{v}{g} = \frac{2 \cdot 19 \frac{m}{s}}{9.81 \frac{m}{s^{2}}} = 3.87 s .$ $t=2v/g=(2*19m/s)/(9.81m/s^2)=3.87s.$
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A projectile is shot from the ground at a velocity of $19 \frac{m}{s}$ $19 m/s$ and at an angle of $\frac{π}{2}$ $(pi)/2$ . How long will it take for the projectile to land?

1 Answer

Explanation:

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A projectile is shot from the ground at a velocity of $19 \frac{m}{s}$ $19 m/s$ and at an angle of $\frac{π}{2}$ $(pi)/2$ . How long will it take for the projectile to land?