Question

A projectile is shot from the ground at a velocity of `2 m/s` and at an angle of `(2pi)/3`. How long will it take for the projectile to land?

Answer 1

`(2sqrt(3))/10` seconds

Explanation:

`T = (2u sin θ) / g`

`T = (2 × 2 ms^-1 sin ((2 π)/3)) / (10 ms^-2)`

`T = (4 × sqrt(3)/2) / (10)` s

`T = (2sqrt(3))/10` `text(seconds)`