A projectile is shot from the ground at a velocity of $2 m/s$ at an angle of $(5pi)/12$ . How long will it take for the projectile to land?

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Answer 1 · 2017-03-27T10:16:21

The time to land $=0.4s$

Solving in the vertical direction $uarr^+$

$u=u_0sintheta=2sin(5/12pi)ms^-1$

$a=-g=-9.8ms^-2$

$v=0$ at the maximum height

We apply the equation

$v=u+at$

$0=2sin(5/12pi) - g*t$

$t=(2sin(5/12pi))/g=0.2s$

This is the time to reach the maximum height

The time to land $=0.2*2=0.4s$

A projectile is shot from the ground at a velocity of 2 m/s2 m/s at an angle of (5pi)/12(5pi)/12. How long will it take for the projectile to land?