A projectile is shot from the ground at a velocity of #24 m/s# and at an angle of #(2pi)/3#. How long will it take for the projectile to land?

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Answer 1 · 2016-01-21T08:24:55

#4.2416 s#

Data:-
Initial velocity#=v_0=24m/s#

Angle of throwing #=theta=(2pi)/3#

Time of flight#=T=??#

Acceleration due to gravity#=g=9.8m/s^2#

Sol:-

We know that:

#T=(2v_0sintheta)/g#

#implies T=(2*24*Sin((2pi)/3))/9.8=(48*0.866)/9.8=4.2416 #

#implies T=4.2416s#

Hence the projectile will land at #4.2416 s# approximately.