A projectile is shot from the ground at a velocity of $25 \frac{m}{s}$ $25 m/s$ and at an angle of $\frac{2 π}{3}$ $(2pi)/3$ . How long will it take for the projectile to land?

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A projectile is shot from the ground at a velocity of $25 \frac{m}{s}$ $25 m/s$ and at an angle of $\frac{2 π}{3}$ $(2pi)/3$ . How long will it take for the projectile to land?

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Answer 1 · 2016-11-16T13:37:19

The time for the projectile to land is 4.41 seconds.

Explanation:

The total time taken to reach ground is the TIME OF FLIGHT.
Time of flight $T = (2 u sin θ) / g$ $T=(2usintheta)//g$
We consider acceleration due to the gravity $'g'=9.8m//s^2$ .
Substituting the numericals we get
$T= [2xx25m//sxxsin(2pi//3)]//9.8m//s^2$ .
$:.T=4.41 seconds$ .

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A projectile is shot from the ground at a velocity of $25 \frac{m}{s}$ $25 m/s$ and at an angle of $\frac{2 π}{3}$ $(2pi)/3$ . How long will it take for the projectile to land?

1 Answer

Explanation:

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A projectile is shot from the ground at a velocity of $25 \frac{m}{s}$ $25 m/s$ and at an angle of $\frac{2 π}{3}$ $(2pi)/3$ . How long will it take for the projectile to land?