A projectile is shot from the ground at a velocity of $3 \frac{m}{s}$ $3 m/s$ and at an angle of $\frac{7 π}{12}$ $(7pi)/12$ . How long will it take for the projectile to land?

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A projectile is shot from the ground at a velocity of $3 \frac{m}{s}$ $3 m/s$ and at an angle of $\frac{7 π}{12}$ $(7pi)/12$ . How long will it take for the projectile to land?

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Answer 1 · 2016-07-07T21:49:52

$0.0196 s$ $0.0196s$

Explanation:

The equation to find time of flight given angle and speed of launch is:
$t = \frac{2 v_{o} sin (θ)}{g}$ $t=(2v_osin(theta))/g$
where:
$t$ $t$ is the time taken to hit the ground
$v_{o}$ $v_o$ is the launch speed of the projectile ( $3 m s^{- 1})$ $3ms^-1)$
$θ$ $theta$ is the angle of launch ( $\frac{7 π}{12}$ $(7pi)/12$ )
$g$ $g$ is the acceleration due to gravity ( $9.81 m s^{- 1}$ $9.81ms^-1$ )

We then substitute these values into the equation

$t = \frac{2 (3 m s^{- 1}) sin (\frac{7 π}{12})}{9.81 m s^{- 1} `}$ $t=(2(3ms^-1)sin((7pi)/12))/(9.81ms^-1`)$

$t = 0.01955 s = 0.0196 s (3 s.f.)$ $t=0.01955s = 0.0196s" (3 s.f.")$

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A projectile is shot from the ground at a velocity of $3 \frac{m}{s}$ $3 m/s$ and at an angle of $\frac{7 π}{12}$ $(7pi)/12$ . How long will it take for the projectile to land?

1 Answer

Explanation:

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A projectile is shot from the ground at a velocity of 3ms3 m/s and at an angle of 7π12(7pi)/12. How long will it take for the projectile to land?

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A projectile is shot from the ground at a velocity of $3 \frac{m}{s}$ $3 m/s$ and at an angle of $\frac{7 π}{12}$ $(7pi)/12$ . How long will it take for the projectile to land?