A projectile is shot from the ground at a velocity of $3 m/s$ at an angle of $pi/4$ . How long will it take for the projectile to land?

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Answer 1 · 2017-12-01T18:08:07

$"0.432 s"$

$v = "3 m/s" = sqrt((v_h)² + (v_v)²)$

$"Angle" = 45^@ => v_"horiz" = v_"vertik" = 3/sqrt(2)$

Since

$v = g t => t = v/g = 3/(sqrt(2) * g)$

$t =$ time to fall, here we have the double of that: rise & fall

$=> T = 6/(sqrt(2) * g) = "0.432 s"$

A projectile is shot from the ground at a velocity of 3 m/s3 m/s at an angle of pi/4pi/4. How long will it take for the projectile to land?