A projectile is shot from the ground at a velocity of $32 m/s$ and at an angle of $(pi)/2$ . How long will it take for the projectile to land?

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Answer 1 · 2016-12-12T19:26:48

$"time elapsed is 6.52 seconds"$

$"t:time elapsed"$
$v_i:"initial velocity"$
$alpha:"angle"$
$g=9.81" "N/(kg)$

$t=(2*v_i*sin alpha)/g$

$t=(2*32*1)/(9.81)$

$t=64/(9.81)$

$t=6.52" "s$

A projectile is shot from the ground at a velocity of 32 m/s32 m/s and at an angle of (pi)/2(pi)/2. How long will it take for the projectile to land?