A projectile is shot from the ground at a velocity of $32 m/s$ and at an angle of $(3pi)/4$ . How long will it take for the projectile to land?

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Answer 1 · 2016-11-02T15:10:15

$t= ( 16 sqrt2)/5 sec$

Here, $u= 32m/s$ , $theta= (3pi)/4$

$t = (2usintheta)/g$

$t= (2xx 32xx 1/sqrt2)/10$

$t= ( 32xx sqrt2/2)/5$

$t= ( 16 sqrt2)/5 sec$

A projectile is shot from the ground at a velocity of 32 m/s32 m/s and at an angle of (3pi)/4(3pi)/4. How long will it take for the projectile to land?