A projectile is shot from the ground at a velocity of $6 \frac{m}{s}$ $6 m/s$ and at an angle of $\frac{7 π}{12}$ $(7pi)/12$ . How long will it take for the projectile to land?

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A projectile is shot from the ground at a velocity of $6 \frac{m}{s}$ $6 m/s$ and at an angle of $\frac{7 π}{12}$ $(7pi)/12$ . How long will it take for the projectile to land?

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Answer 1 · 2016-02-13T10:37:43

$t_{e} ≅ 1, 182 s$ $t_e~=1,182s$

Explanation:

$t_{e} : time elapsed ; v_{i} : initial velocity ; α : angle$ $t_e:" time elapsed ; " v_i: "initial velocity ; "alpha:"angle"$
$t_{e} = \frac{2 \cdot v_{i} \cdot sin α}{g}$ $t_e=(2*v_i*sin alpha)/g$
$α = \frac{7 π}{12} \cdot \frac{180}{π} = 105^{o}$ $alpha=(7 pi)/12*180/pi=105^o$
$sin 105 = sin 75 = 0, 966 g:9,81$ $sin 105=sin 75=0,966" g:9,81"$
$t_{e} = \frac{2 \cdot 6 \cdot 0, 966}{9, 81}$ $t_e=(2*6*0,966)/(9,81)$
$t_{e} ≅ 1, 182 s$ $t_e~=1,182s$

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A projectile is shot from the ground at a velocity of $6 \frac{m}{s}$ $6 m/s$ and at an angle of $\frac{7 π}{12}$ $(7pi)/12$ . How long will it take for the projectile to land?

1 Answer

Explanation:

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A projectile is shot from the ground at a velocity of $6 \frac{m}{s}$ $6 m/s$ and at an angle of $\frac{7 π}{12}$ $(7pi)/12$ . How long will it take for the projectile to land?