A projectile is shot from the ground at a velocity of $7 \frac{m}{s}$ $7 m/s$ at an angle of $\frac{5 π}{12}$ $(5pi)/12$ . How long will it take for the projectile to land?

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A projectile is shot from the ground at a velocity of $7 \frac{m}{s}$ $7 m/s$ at an angle of $\frac{5 π}{12}$ $(5pi)/12$ . How long will it take for the projectile to land?

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Answer 1 · 2016-03-12T03:34:49

$\approx 1.38 s$ $~~1.38s$

Explanation:

velocity of projection $u = 7 m s^{- 1}$ $u=7ms^-1$
angle of projection, $α = 5 \frac{π}{12}$ $alpha=5pi/12$
If time of flight be T s
then
$0 = u sin α \times T - \frac{1}{2} \times g \times T^{2}$ $0=usinalphaxxT-1/2xxgxxT^2$

$\Rightarrow T = \frac{2 u sin α}{g} = (2 \times 7 \times \frac{sin (5 \frac{π}{12})}{9.8}) \approx 1.38 s$ $=>T=(2usinalpha)/g=(2xx7xxsin(5pi/12)/9.8)~~1.38s$

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A projectile is shot from the ground at a velocity of $7 \frac{m}{s}$ $7 m/s$ at an angle of $\frac{5 π}{12}$ $(5pi)/12$ . How long will it take for the projectile to land?

1 Answer

Explanation:

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A projectile is shot from the ground at a velocity of 7ms7 m/s at an angle of 5π12(5pi)/12. How long will it take for the projectile to land?

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Explanation:

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A projectile is shot from the ground at a velocity of $7 \frac{m}{s}$ $7 m/s$ at an angle of $\frac{5 π}{12}$ $(5pi)/12$ . How long will it take for the projectile to land?