A projectile is shot from the ground at a velocity of $7 \frac{m}{s}$ $7 m/s$ at an angle of $\frac{π}{3}$ $pi/3$ . How long will it take for the projectile to land?

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A projectile is shot from the ground at a velocity of $7 \frac{m}{s}$ $7 m/s$ at an angle of $\frac{π}{3}$ $pi/3$ . How long will it take for the projectile to land?

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Answer 1 · 2016-01-11T13:12:49

Data:-
Muzzle velocity $=$ $=$ Initial velocity $= v_{0} = 7 \frac{m}{s}$ $=v_0=7m/s$

Angle $= θ = \frac{π}{3}$ $=theta=(pi)/3$

Time of flight $= T = ? ?$ $=T=??$
Sol:-
$T = \frac{2 v_{0} sin θ}{g}$ $T=(2v_0Sintheta)/g$

$\Rightarrow T = \frac{2 \cdot 7 sin (\frac{π}{3})}{9.8} = \frac{14 \cdot 0.866}{9.8} = \frac{12.124}{9.8} = 1.2371 s$ $implies T=(2*7sin((pi)/3))/9.8=(14*0.866)/9.8=12.124/9.8=1.2371s$

$\Rightarrow T = 1.2371 s$ $implies T=1.2371s$

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A projectile is shot from the ground at a velocity of $7 \frac{m}{s}$ $7 m/s$ at an angle of $\frac{π}{3}$ $pi/3$ . How long will it take for the projectile to land?

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