A projectile is shot from the ground at a velocity of $7 m/s$ at an angle of $pi/4$ . How long will it take for the projectile to land?

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Answer 1 · 2017-10-11T17:10:51

$t=(7sqrt2)/20s$

to find the time of flight we use the vertical components

so vertically

$u_y=7sin(pi/4)=(7sqrt2)/2ms^(-1)$

$s_y=0m$

$g=-10ms^(-2)$

vertically

$s_y=u_yt+1/2g t^2$

$=>0=(7sqrt2)/2t-10t^2$

$0=t ((7sqrt2)/2-10t)$

$t=0" "$ this is the initial point of the trajectory

$:.(7sqrt2)/2-10t=0$

$t=(7sqrt2)/20s$

A projectile is shot from the ground at a velocity of 7 m/s7 m/s at an angle of pi/4pi/4. How long will it take for the projectile to land?